1888 MLB Wins by Team
Every team's total, added up from its players' lines. Games won
The St. Louis Browns led all of MLB in wins in 1888, with 92, 4 ahead of the Brooklyn Bridegrooms. The average across 16 MLB teams is 66.8.
Led all of MLB in 1888
St. Louis Browns
137 games
92
Wins
4 clear of Brooklyn Bridegrooms
| # | Team | League | G | W |
|---|---|---|---|---|
| 1 |
St. Louis Browns
|
AA | 137 | 92 |
| 2 |
 Brooklyn Bridegrooms
|
AA | 143 | 88 |
| 3 |
 New York Giants
|
NL | 137 | 83 |
| 4 | Philadelphia Athletics | AA | 136 | 81 |
| 5 |
 Cincinnati Red Stockings
|
AA | 137 | 80 |
| 6 |
 Chicago White Stockings
|
NL | 135 | 77 |
| 7 |
 Boston Beaneaters
|
NL | 137 | 70 |
| 8 | Detroit Wolverines | NL | 134 | 68 |
| 8 |
 Philadelphia Quakers
|
NL | 131 | 68 |
| MLB average | 66.8 | |||
| 10 |
 Pittsburg Alleghenys
|
NL | 138 | 66 |
| 11 | Baltimore Orioles | AA | 137 | 57 |
| 12 | Cleveland Blues | AA | 135 | 50 |
| 12 | Indianapolis Hoosiers | NL | 136 | 50 |
| 14 | Louisville Colonels | AA | 139 | 48 |
| 14 | Washington Nationals | NL | 136 | 48 |
| 16 | Kansas City Cowboys | AA | 132 | 43 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.