1893 MLB Winning Percentage by Team
Every team's total, added up from its players' lines. Wins per decision
The Boston Beaneaters led all of MLB in winning percentage in 1893, with .667, .039 ahead of the Pittsburgh Pirates. The average across 12 MLB teams is .500.
Led all of MLB in 1893
Boston Beaneaters
131 games
.667
Winning Percentage
.039 clear of Pittsburgh Pirates
| # | Team | League | G | W-L% |
|---|---|---|---|---|
| 1 |
Boston Beaneaters
|
NL | 131 | .667 |
| 2 |
 Pittsburgh Pirates
|
NL | 131 | .628 |
| 3 | Cleveland Spiders | NL | 129 | .570 |
| 4 |
 Philadelphia Phillies
|
NL | 133 | .558 |
| 5 |
 New York Giants
|
NL | 136 | .515 |
| 6 |
 Brooklyn Grooms
|
NL | 130 | .508 |
| 6 |
 Cincinnati Reds
|
NL | 131 | .508 |
| MLB average | .500 | |||
| 8 | Baltimore Orioles | NL | 130 | .462 |
| 9 |
 Chicago Colts
|
NL | 128 | .441 |
| 10 |
 St. Louis Browns
|
NL | 135 | .432 |
| 11 | Louisville Colonels | NL | 126 | .400 |
| 12 | Washington Senators | NL | 130 | .310 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.