1896 MLB Losses by Team
Every team's total, added up from its players' lines. Games lost
The Louisville Colonels led all of MLB in losses in 1896, with 93, 3 ahead of the St. Louis Browns. The average across 12 MLB teams is 64.8.
Led all of MLB in 1896
Louisville Colonels
134 games
93
Losses
3 clear of St. Louis Browns
| # | Team | League | G | L |
|---|---|---|---|---|
| 1 | Louisville Colonels | NL | 134 | 93 |
| 2 |
 St. Louis Browns
|
NL | 131 | 90 |
| 3 |
 Brooklyn Bridegrooms
|
NL | 133 | 73 |
| 3 | Washington Senators | NL | 133 | 73 |
| 5 |
 Philadelphia Phillies
|
NL | 130 | 68 |
| 6 |
 New York Giants
|
NL | 133 | 67 |
| MLB average | 64.8 | |||
| 7 |
 Pittsburgh Pirates
|
NL | 131 | 63 |
| 8 |
 Boston Beaneaters
|
NL | 132 | 57 |
| 8 |
 Chicago Colts
|
NL | 132 | 57 |
| 10 |
 Cincinnati Reds
|
NL | 128 | 50 |
| 11 | Cleveland Spiders | NL | 135 | 48 |
| 12 | Baltimore Orioles | NL | 132 | 39 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.