1948 MLB Doubles by Team

The Boston Red Sox led all of MLB in doubles in 1948, with 277, 5 ahead of the Boston Braves. The average across 28 MLB teams is 153.1.

Led all of MLB in 1948 Boston Red Sox 155 games

277 Doubles 5 clear of Boston Braves

#	Team	League	G	2B
1	Boston Red Sox	AL	155	277
2	Boston Braves	NL	154	272
3	Brooklyn Dodgers	NL	155	256
4	New York Yankees	AL	154	251
4	St. Louis Browns	AL	155	251
6	Cleveland Indians	AL	156	242
7	St. Louis Cardinals	NL	155	238
8	Philadelphia Athletics	AL	154	231
9	Philadelphia Phillies	NL	155	227
10	Chicago Cubs	NL	155	225
11	Cincinnati Reds	NL	153	221
12	Detroit Tigers	AL	154	219
13	New York Giants	NL	155	210
14	Washington Senators	AL	154	203
15	Pittsburgh Pirates	NL	156	191
16	Chicago White Sox	AL	154	172
	MLB average			153.1
17	Kansas City Monarchs	NAL	80	100
18	Baltimore Elite Giants	NN2	73	83
19	New York Cubans	NN2	45	76
20	Philadelphia Stars	NN2	59	65
21	Homestead Grays	NN2	62	54
22	Birmingham Black Barons	NAL	78	49
23	Newark Eagles	NN2	57	46
24	Cleveland Buckeyes	NAL	87	34
25	Indianapolis Clowns	NAL	76	30
26	Chicago American Giants	NAL	78	22
26	Memphis Red Sox	NAL	91	22
28	New York Black Yankees	NN2	46	20

A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.