1996 MLB Winning Percentage by Team
Every team's total, added up from its players' lines. Wins per decision
The Cleveland Indians led all of MLB in winning percentage in 1996, with .615, .022 ahead of the Atlanta Braves. The average across 28 MLB teams is .500.
Led all of MLB in 1996
Cleveland Indians
161 games
.615
Winning Percentage
.022 clear of Atlanta Braves
| # | Team | League | G | W-L% |
|---|---|---|---|---|
| 1 |
Cleveland Indians
|
AL | 161 | .615 |
| 2 |
 Atlanta Braves
|
NL | 162 | .593 |
| 3 |
 New York Yankees
|
AL | 162 | .568 |
| 4 |
 San Diego Padres
|
NL | 162 | .562 |
| 5 |
 Los Angeles Dodgers
|
NL | 162 | .556 |
| 5 |
 Texas Rangers
|
AL | 163 | .556 |
| 7 |
 Baltimore Orioles
|
AL | 163 | .543 |
| 7 |
 Montreal Expos
|
NL | 162 | .543 |
| 7 |
 St. Louis Cardinals
|
NL | 162 | .543 |
| 10 |
 Seattle Mariners
|
AL | 161 | .528 |
| 11 |
 Boston Red Sox
|
AL | 162 | .525 |
| 11 |
 Chicago White Sox
|
AL | 162 | .525 |
| 13 |
 Colorado Rockies
|
NL | 162 | .512 |
| 14 |
 Houston Astros
|
NL | 162 | .506 |
| MLB average | .500 | |||
| 15 |
 Cincinnati Reds
|
NL | 162 | .500 |
| 16 |
 Florida Marlins
|
NL | 162 | .494 |
| 16 |
 Milwaukee Brewers
|
AL | 162 | .494 |
| 18 |
 Minnesota Twins
|
AL | 162 | .482 |
| 18 |
 Oakland Athletics
|
AL | 162 | .482 |
| 20 |
 Chicago Cubs
|
NL | 162 | .469 |
| 21 |
 Kansas City Royals
|
AL | 161 | .466 |
| 22 |
 Toronto Blue Jays
|
AL | 162 | .457 |
| 23 |
 Pittsburgh Pirates
|
NL | 162 | .451 |
| 24 |
 New York Mets
|
NL | 162 | .438 |
| 25 |
 California Angels
|
AL | 161 | .435 |
| 26 |
 San Francisco Giants
|
NL | 162 | .420 |
| 27 |
 Philadelphia Phillies
|
NL | 162 | .414 |
| 28 |
 Detroit Tigers
|
AL | 162 | .327 |
A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.