1999 MLB Doubles by Team

The Toronto Blue Jays led all of MLB in doubles in 1999, with 337, 3 ahead of the Boston Red Sox. The average across 30 MLB teams is 291.3.

Led all of MLB in 1999 Toronto Blue Jays 162 games

337 Doubles 3 clear of Boston Red Sox

#	Team	League	G	2B
1	Toronto Blue Jays	AL	162	337
2	Boston Red Sox	AL	162	334
3	Montreal Expos	NL	162	320
4	Cincinnati Reds	NL	163	312
5	Atlanta Braves	NL	162	309
5	Cleveland Indians	AL	162	309
7	San Francisco Giants	NL	162	307
8	Colorado Rockies	NL	162	305
9	Texas Rangers	AL	162	304
10	New York Yankees	AL	162	302
10	Philadelphia Phillies	NL	162	302
12	Baltimore Orioles	AL	162	299
12	Milwaukee Brewers	NL	161	299
14	Chicago White Sox	AL	162	298
15	New York Mets	NL	163	297
16	Kansas City Royals	AL	161	294
17	Houston Astros	NL	162	293
	MLB average			291.3
18	Arizona Diamondbacks	NL	162	289
18	Detroit Tigers	AL	161	289
20	Oakland Athletics	AL	162	287
21	Minnesota Twins	AL	161	285
22	Pittsburgh Pirates	NL	161	282
23	St. Louis Cardinals	NL	161	274
24	Tampa Bay Devil Rays	AL	162	272
25	Florida Marlins	NL	162	266
26	Seattle Mariners	AL	162	263
27	San Diego Padres	NL	162	256
28	Chicago Cubs	NL	162	255
29	Los Angeles Dodgers	NL	162	253
30	Anaheim Angels	AL	162	248

A team's total is its players' numbers for the club added up, so a player traded mid-season counts for each team only what he did there. Rates such as ERA and batting average are worked out from the team's summed totals, not averaged across players.